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Euclid: Elementa

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gre I,43
Ἐπεὶ γὰρ παραλληλόγραμμόν ἐστι τὸ ΑΒΓΔ, διάμετρος δὲ αὐτοῦ ἡ ΑΓ, ἴσον ἐστὶ τὸ ΑΒΓ τρίγωνον τῷ ΑΓΔ τριγώνῳ.
Pic374
Pic652
eng
For, since ABCD is a parallelogram, and AC its diameter, the triangle ABC is equal to the triangle ACD. [I. 34]
lat Sic
Quoniam enim parallilogrammum est ABGD, diametros vero ipsius AG, equale est ABG trigonum trigono AGD.
lat Gerard
Probatio huius: Quia superficies ABGD equidistantium existit laterum et diametrus eius est DB, erit triangulus ABD triangulo DBG equalis.
lat Adelard
Rationis causa: Superficie etenim ABGD existente laterum equidistanium diametroque BG, erit triangulus ABG sicut triangulus DBG.
lat Hermann
Primo quoniam ipsa superficies tota equidistancium est, deinde componitur diameter recta, que spaciis altrinsecis equalitatis causa erit, est itaque triangulus ABG equalis ei quem DBG conficiunt.
ara Uppsala
No Arabic
ara Tuṣi
[...]
ara Nairizi p. 166
برهانه ان سطح (ا ب ج د) متوازى الاضلاع وقطر (ب ج)
san 58,19-21
atropapattiḥ | tabakajhacaturbhujaṃ hajhavadacaturbhujaṃ caitau samānānantarabhujau staḥ | punaḥ abadatribhujaṃ bajadatribhujaṃ bṛhaccaturbhujasya samānaṃ bhagadvayam asti |
Pic758
lat Clavius
Cum enim triangula A B C, C D A, æqualia sint;
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