Let there be set out two rational straight lines AB, BC commensurable in square only and such that the square on the greater AB is greater than the square on the less BC by the square on a straight line incommensurable with AB, [X. 30] let BC be bisected at D, let there be applied to AB a parallelogram equal to the square on either of the straight lines BD, DC and deficient by a square figure, and let it be the rectangle AE, EB; [VI. 28]
Adiaceant due rite potentia solum commensurabiles AB, BG ut maior AB minore BG maius possit eo quod ab incommensurabili sibi. Et dividatur recta BG in duo equalia secundum punctum D. Et ei quod ab utralibet rectarum BD, DG equale secundum rectam AB educatur parallilogrammum deficiens forma tetragona sitque quod sub rectis AEB.