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Euclid: Elementa
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PROPOSITION 14. 
 
 
If four straight lines be proportional, and the square on the first be greater than the square on the second by the square on a straight line commensurable with the first, the square on the third will also be greater than the square on the fourth by the square on a straight line commensurable with the third. And, if the square on the first be greater than the square on the second by the square on a straight line incommensurable with the first, the square on the third will also be greater than the square on the fourth by the square on a straight line incommensurable with the third. 
 
 
Let A, B, C, D be four straight lines in proportion, so that, as A is to B, so is C to D; and let the square on A be greater than the square on B by the square on E, and let the square on C be greater than the square on D by the square on F;  I say that, if A is commensurable with E, C is also commensurable with F, and, if A is incommensurable with E, C is also incommensurable with F. 
   
   
For since, as A is to B, so is C to D, therefore also, as the square on A is to the square on B, so is the square on C to the square on D. [VI. 22]  But the squares on E, B are equal to the square on A, and the squares on D, F are equal to the square on C.  Therefore, as the squares on E, B are to the square on B, so are the squares on D, F to the square on D;  therefore, separando, as the square on E is to the square on B, so is the square on F to the square on D; [V. 17]  therefore also, as E is to B, so is F to D; [VI. 22]  therefore, inversely, as B is to E, so is D to F.  But, as A is to B, so also is C to D;  therefore, ex aequali, as A is to E, so is C to F. [V. 22]  Therefore, if A is commensurable with E, C is also commensurable with F, and, if A is incommensurable with E, C is also incommensurable with F. [X. 11] 
                 
                 
Therefore etc.2 
 
 
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