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Euclid: Elementa

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Click to Expand/Collapse OptionTitle
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PROPOSITION 31. 
 
 
To find two medial straight lines commensurable in square only, containing a rational rectangle, and such that the square on the greater is greater than the square on the less by the square on a straight line commensurable in length with the greater. 
 
 
Let there be set out two rational straight lines A, B commensurable in square only and such that the square on A, being the greater, is greater than the square on B the less by the square on a straight line commensurable in length with A. [X. 29]  And let the square on C be equal to the rectangle A, B.  Now the rectangle A, B is medial; [X. 21]  therefore the square on C is also medial;  therefore C is also medial. [X. 21]  Let the rectangle C, D be equal to the square on B.  Now the square on B is rational;  therefore the rectangle C, D is also rational.  And since, as A is to B, so is the rectangle A, B to the square on B,  while the square on C is equal to the rectangle A, B, and the rectangle C, D is equal to the square on B,  therefore, as A is to B, so is the square on C to the rectangle C, D.  But, as the square on C is to the rectangle C, D, so is C to D;  therefore also, as A is to B, so is C to D.  But A is commensurable with B in square only;  therefore C is also commensurable with D in square only. [X. 11]  And C is medial;  therefore D is also medial. [X. 23, addition]  And since, as A is to B, so is C to D, and the square on A is greater than the square on B by the square on a straight line commensurable with A,  therefore also the square on C is greater than the square on D by the square on a straight line commensurable with C. [X. 14] 
                                     
                                     
Therefore two medial straight lines C, D, commensurable in square only and containing a rational rectangle, have been found, and the square on C is greater than the square on D by the square on a straight line commensurable in length with C. 
 
 
Similarly also it can be proved that the square on C exceeds the square on D by the square on a straight line incommensurable with C,  when the square on A is greater than the square on B by the square on a straight line incommensurable with A. [X. 30] 
   
   
 
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