For, if they are commensurable, some magnitude will measure them.
Let a magnitude measure them, if possible, and let it be E;
let AB, measuring FD, leave CF less than itself, let CF measuring BG, leave AG less than itself,
and let this process be repeated continually, until there is left some magnitude which is less than E.
Suppose this done, and let there be left AG less than E.
Then, since E measures AB, while AB measures DF, therefore E will also measure FD.
But it measures the whole CD also;
therefore it will also measure the remainder CF.
But CF measures BG;
therefore E also measures BG.
But it measures the whole AB also;
therefore it will also measure the remainder AG, the greater the less: which is impossible.
Therefore no magnitude will measure the magnitudes AB, CD;
therefore the magnitudes AB, CD are incommensurable.
Complete text
Book I