For, if possible, let it be divided at D also, so that AD, DB are also incommensurable in square and make the sum of the squares on AD, DB rational, but the rectangle contained by them medial.
Then, since that by which the squares on AC, CB differ from the squares on AD, DB is also that by which twice the rectangle AD, DB differs from twice the rectangle AC, CB,
while the squares on AC, CB exceed the squares on AD, DB by a rational area — for both are rational —
therefore twice the rectangle AD, DB also exceeds twice the rectangle AC, CB by a rational area, though they are medial: which is impossible. [X. 26 ]
Therefore a major straight line is not divided at different points;
therefore it is only divided at one and the same point.
Q. E. D.
Complete text
Book I