For since, whatever part A is of BC, D is also the same part of EF,
therefore, as many numbers as there are in BC equal to A, so many numbers are there also in EF equal to D.
Let BC be divided into the numbers equal to A, namely BG, GC, and EF into the numbers equal to D, namely EH, HF;
then the multitude of BG, GC will be equal to the multitude of EH, HF.
And, since BG is equal to A, and EH to D, therefore BG, EH are also equal to A, D.
For the same reason GC, HF are also equal to A, D.
Therefore, as many numbers as there are in BC equal to A, so many are there also in BC, EF equal to A, D.
Therefore, whatever multiple BC is of A, the same multiple also is the sum of BC, EF of the sum of A, D.
Therefore, whatever part A is of BC, the same part also is the sum of A, D of the sum of BC, EF.
Q. E. D.
Complete text
Book I